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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | ||
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ | $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ | ||
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Revision as of 11:24, 3 April 2016
<script type="text/x-mathjax-config">
MathJax.Hub.Config({tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}});
</script>
<script type="text/javascript" async
src="https://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS_CHTML">
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$