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$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ | $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ | ||
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Revision as of 11:23, 3 April 2016
<head>
<title>MathJax TeX Test Page</title>
<script type="text/x-mathjax-config">
MathJax.Hub.Config({tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}});
</script> <script type="text/javascript" async
src="https://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS_CHTML">
</script> </head> <body> When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ </body>